debug mod_rewrite

Is there a tool or a method to help debug mod_rewrite?

My immediate problem is that given

RewriteRule ^(.*)2z$ $0.jpg [L]
and http://example.org/3z.2z
I get "The requested URL /3z.2z.jpg was not found on this server."
I would expect to get /3z..jpg

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Sig
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caff987@logsin.org (Sig) wrote:

> Is there a tool or a method to help debug mod_rewrite?
>
> My immediate problem is that given
>
> RewriteRule ^(.*)2z$ $0.jpg [L]
^
$1?
<http://httpd.apache.org/docs/2.1/mod/mod_rewrite.html#rewriterule>
see beneath: "Here are all possible substitution combinations and their
meanings:"

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On 19 Sep 2005 01:49:29 GMT, John Bokma <john@castleamber.com> wrote:

>caff987@logsin.org (Sig) wrote:
>
>> Is there a tool or a method to help debug mod_rewrite?
>>
>> My immediate problem is that given
>>
>> RewriteRule ^(.*)2z$ $0.jpg [L]
> ^
> $1?

It was the $0. Thank you.

(A tool, if there is one, would still be nice.)
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Sig
(add three to my address to avoid spam filter)

Sig wrote:

> On 19 Sep 2005 01:49:29 GMT, John Bokma <john@castleamber.com> wrote:
>
>>caff987@logsin.org (Sig) wrote:
>>
>>> Is there a tool or a method to help debug mod_rewrite?
>>>
>>> My immediate problem is that given
>>>
>>> RewriteRule ^(.*)2z$ $0.jpg [L]
>> ^
>> $1?
>
> It was the $0. Thank you.
>
> (A tool, if there is one, would still be nice.)


Given that the regular regular expressions are largely Perl compatible, you
could easy test it with Perl.


$ perl -e '$uri = "3z.2z"; $uri =~ s!^(.*)2z$!$1.jpg!; print "$uri\n";'

3z..jpg


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